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**Check if I'm right??* The point A(-2, 3) is translated using T: (x,y) → (x + 4, y + 2). What is the distance from A to A'? sqrt6 2sqrt2 5 2sqrt5 ^^ I think it's B.
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along 4 then up 2 so itt forms right angled traingle
|dw:1462991266043:dw|
\[A=(-2+4,3+2)\] or \[A=(2,5)\]
use pythagoras theorem
AA' = sqrt (2^2 + 4^2)
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Its not |B
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