Question

.....

Answer 1

For (g + h)(x), this is the same thing as g(x) + h(x). So what you would do is \((3x + 2) + (6x)\). Combine like terms and that would be your answer.

Answer 2

For (g*h)(x), this would be once again the same thing but you would need to multiply the functions out \(g(x) \times h(x)\).

For (g-h)(-1), this time you would need to substitute -1 for wherever the x is in both of the functions to get \(3(-1) + 2) - 6(-1)\).

Answer 3

Do you understand this? @anonymous97

Answer 4

Let's check
1) 3x + 2 + 6x = \(\color{green}{9x + 2}\)
2) 6x(3x +2) = \(\color{green}{18x^2 + 12x}\)
3) (3(-1) + 2) - 6(-1) = (-3 + 2) - 6(-1) = -1 + 6 = 5