Question

Check my answer
Use the binomial theorem to expand (3x-2y)^4

Answer 1

4!/4−0!0!(( 3x )^n – k ( − 2y )^ k) + 4!/ 4−1!1! (( 3x )^n – k ( − 2y )^ k) + 4! /4−2!2! (( 3x )^n – k ( − 2y )^ k) + 4!/ 4−3!3! (( 3x )^n – k ( − 2y )^ k)+ 4!/ 4−3!3! (( 3x )^n – k ( − 2y )^ k)

Answer 2

4!/4−0!0! (( 3x ) ^4 – 0 ( − 2y )^ 0) + 4!/4-1!1! (( 3x )^ 4– 1 ( − 2y )) + 4!/4-2!2!(( 3x ) ^4 – 2 ( − 2y )^ 2) + 4!/4-3!3! (( 3x )^ 4 – 3 ( − 2y )^ 3)+ 4!/4-4!4! (( 3x ) ^4 – 4 ( − 2y ) 4) ^4

Answer 3

1 (( 3x )^4 ( −2y )^0 ) + 4 (( 3x )^3 ( −2y )) + 6 (( 3x )^ 2 ( −2y )^ 2) + 4 (( 3x )( −2y )^ 3) + 1 (( 3x )^ 0 ( −2y )^ 4)

Answer 4

I'm going to break it down into steps for easy math

Answer 5

Step 1
1 (( 3x )^4 ( −2y )^0 )
1(3 ^4 x^4 ( −2y )^0 )
1(81x^4 (−2y)^0)
1(81x^4 (−2)0y^0 ))
1(81x^4(1y^0))
1(81x^4(1⋅1))
1⋅1(81x^4(1))
1(81x^4)
81x^4

Answer 6

Step 2
+ 4 (( 3x )^3 ( −2y ))
+ 4(3^3x^3(−2y))
+ 4(27x^3(−2y))
+ 4(−54x^3y)
− 216(x^3y)
− 216x^3y

Answer 7

Step 3
+ 6((3x)^2(−2y)^2)
+ 6(3^2 x^2 (−2y)^2)
+ 6(9x^2 (−2y)^2)
+ 6(9x^2((−2)^2y^2))
+ 6(9x^2(4y^2))
+ 6(36x^2y^2)
+ 216x^2y^2

Answer 8

Step 4
+ 4((3x)(−2y)^3)
+ 4(3x((−2)^3 y^3 ))
+ 4(3x(−8y^3))
+ 4(−24xy^3)
− 96(xy^3)
- 96xy^3

Answer 9

Step 5
+ 1(( 3x)^0 ( −2y )^4)
+ 1( 30x^0 ( −2y )^4)
+ 1(1x^0 ( −2y )^4)
+ 1( (−2y )^4y^4)
+ 1( 16y^4)
+ 16y^4

Answer 10

Answer:
81x^4 − 216x^3y + 216x^2y^2 − 96xy^3 + 16y^4

Answer 11

Correct.