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9^x-4 = (1/27)
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I would recommend using the common base of 3. Also 1/27 = 27^-1, that should help. See if you can start the question using that.
how is 1/27 = 27^1 ?
It's 27^-1. The negative is important
Okay I'm lost of what to do next , I've put down the 9^x-4 = 27^-1
So do the left side first, how you you get 9^x-4 to have a base of 3?
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3^2 ? and for 27 it's 3^3 ?
Yes, great, so now distribute the ^2 and the ^3 to their respective exponents.
I got 5/2 ?
Yeah, that's right. You can double check yourself using the original equation.
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