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Mathematics 11 Online
OpenStudy (sphott51):

9^x-4 = (1/27)

OpenStudy (erak):

I would recommend using the common base of 3. Also 1/27 = 27^-1, that should help. See if you can start the question using that.

OpenStudy (sphott51):

how is 1/27 = 27^1 ?

OpenStudy (erak):

It's 27^-1. The negative is important

OpenStudy (sphott51):

Okay I'm lost of what to do next , I've put down the 9^x-4 = 27^-1

OpenStudy (erak):

So do the left side first, how you you get 9^x-4 to have a base of 3?

OpenStudy (sphott51):

3^2 ? and for 27 it's 3^3 ?

OpenStudy (erak):

Yes, great, so now distribute the ^2 and the ^3 to their respective exponents.

OpenStudy (sphott51):

I got 5/2 ?

OpenStudy (erak):

Yeah, that's right. You can double check yourself using the original equation.

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