Question

Two dice are tossed together. What is the probability of getting an odd number on the second die and a total of five?

Answer 1

@welshfella Could you help me, please?

Answer 2

3/12?

Answer 3

@ShelbyWyatt That's not one of the options.
The options are:
1/8
11/18
7/18
4/9

Answer 4

@FaiqRaees Could you maybe help me with this, please?

Answer 5

my guess is 1/8

Answer 6

a guess is not much use

please show some working

Answer 7

⇒ odds in favour of E1 = P(E1)/[1 – P(E1)] = (1/9)/(1 – 1/9) = 1/8.

Answer 8

It seems to me that the only throws that produce the result are

2,3
4,1

which would resuult in 2/36 as the odds

but that is not an option - so

maybe
3,2
1,4 also count

giving 4/36

Hmm - not getting this...

Answer 9

http://www.math-only-math.com/probability-for-rolling-two-dice.html

Answer 10

section i

Answer 11

you could list all the favourable results
first second
2 3
4 1


which gives a probability of 2 / 36

Answer 12

the second die must give an odd number

Answer 13

the dice are thrown 'together' so strictly there is no 'second die

so as I said above 4/36 seems an option - but it is not in the answer....

Answer 14

AH yes together . so you can count any one of them as a second die. Correct.

Answer 15

Let E1 be the event of getting the sum 5. Then,
E1 = {(1, 4), (2, 3), (3, 2), (4, 1)}
⇒ P(E1) = 4
Therefore, P(E1) = n(E1)/n(S) = 4/36 = 1/9
⇒ odds in favour of E1 = P(E1)/[1 – P(E1)] = (1/9)/(1 – 1/9) = 1/8.

Answer 16

any of you understand, cuz i dont

Answer 17

hmmm But the question asks for the probability

Answer 18

it doesnt ask for the 'odds' it asks for the probability

I understand your point - and it matcjes an answer - but not the way the question is asked in my mind.

E.g.

the probability of throwing a 6 on 1 die is 1:6
The ODDS of throwing a 6 is 1:5

Answer 19

yeah..

Answer 20

yae the odds are given as a ratio

Answer 21

Are you sure you have the correct options, @tayaiv ?

Answer 22

@welshfella

Answer 23

... -.-

Answer 24

Thank you all for trying to figure this out with me, by the way. I really appreciate your help!

Answer 25

so you would have to guess it?

Answer 26

@ShelbyWyatt No, I'm still trying to figure it out myself. I won't guess

Answer 27

I think the answer is 1/18.
@mrnood was right: 4/36 includes all of the possibilities of getting 5, if we consider (1,4) and (4,1) different options.
The probability of getting an odd number on the second die is 3/6 or 1/2.
So, 1/2 * 4/36 = 1/18

What do you think?

Answer 28

sound good

Answer 29

Thank you all!!

Answer 30

I don't agree-

the 2 results are not independent

you cannot throw a 5 on 1 dice and get a sum of 5

Answer 31

and 1/18 is not an answer option anyhow

Answer 32

I think the question has not been worded very well. If it said a die is tossed twice the answer would definitely be 1/18. I would put 1/18 as the answer anyway.

Answer 33

I still disagree

the calculation is based on a 0.5 proability of thraowin ODD on second die.
BUT a throw of 5 is NOT a success (because the toatal cannot be 5)

The calculation used above is that for independent events (i.e. what is the chance of throwin 2 dice and scoring 5 AND throwing 1 dice and getting ODD)

Answer 34

lol

Answer 35

Surely its a TOTAL of 5 - the favourable results are 1 and 4 , and 2 and 3 which is 2 results out of a possible 36.

Answer 36

the scoring of 5 total on 2 dice thrown together has a probability of 1/9

(1,4) (4,1) (2,3) (3,2)

HOWEVER this cannot be combined with the probability of thraowin ODD on one of the dice (0.5) because they are not independent - i.e. you cannot throw a 5 on 1 dice AND score a total of 5.

Therefore 1/9* 1/2 is not vallid because this is only valid for independent events.
(and 1/18 is not an option anyhow)

@tayaiv
are your answers correct (you wrote 11/18 - is it possible that should be 1/18??)

Answer 37

1/18 is an option given in the picture that tayaiv posted