Question

I'm looking for...


...help :D I think it's A. Am I correct?

What is the solution to the equation 9(x + 1) = 27?


x = 2.5 <---
x = 0.5
x = −0.5
x = −3.5

Answer 1

okay so step #1 we can divide both sides by 9

Answer 2

hey @VladthePro this is the problem right 9(x+1) = 27

Answer 3

Sorry abt that it's 9^(x+1) = 27

Answer 4

oh no wonder lol

Answer 5

okay so far

\[9 = 3^{2}\]

\[27 = 3^{3}\]

agree?

Answer 6

yes

Answer 7

If you haven't learned logs yet, you can change the bases

\[3^{2*(x+1)} = 3^{3}\]

Answer 8

so that the bases are both 3 now you can solve it like any other equation

first.

pretend the bases aren't there.

2(x+1) = 3

2x+2 = 3

2x = 1

x = 0.5

Answer 9

\[9^{0.5+1} = 9^{\frac{ 3 }{ 2 }} = 27 \]

Answer 10

let's do it another way, have you learned about logs?

Answer 11

Yes, but still not that good at them yet

Answer 12

\[9^{3/2} = \sqrt[2]{9^{3}} = \sqrt{729} = 27\]

Answer 13

yeah so let's do it the other way

\[9^{x+1} = 27 \]

First we apply the product rule of logs

\[\log_{b}(x^{y}) = y*\log_{b}(x)\]

Then we just solve it like any other equation

\[(x+1)Log_{10}*9 = Log(27)\]

\[xlog*9+\log_{10}9 = Log_{10}(27)\]

\[\frac{ (Log_{10}27-\log_{10}9) }{ Log_{10}~9 } = \frac{ 1 }{ 2 }\]

Answer 14

Oh i see now. Thx for taking ur time to help me :)

Answer 15

yeah np