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Mathematics 14 Online
OpenStudy (anonymous):

EASY MEDAL

OpenStudy (anonymous):

How do you find the point of intersection(s) for x = 2y2 + 3y + 1 and 2x + 3y2 = 0 A) You cannot find points of intersections for non-functions. B) Plug in 0 for x into both equations and solve for y. Then plug that answer back into the other equation to find the corresponding x-coordinate. C) Solve both equations for x and set them equal to each other. This will give you the y-coordinates of the points of intersection. Then plug back into one of the equations to find the corresponding x-coordinates. D) Solve both equations for y and set them equal to each other. This will give you the x-coordinates of the points of intersection. Then plug back into one of the equations to find the corresponding y-coordinates.

OpenStudy (photon336):

You would probably need to set both equations equal to each-other

OpenStudy (photon336):

A better way would be substitution

OpenStudy (anonymous):

I DON'T KNOW HOW

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