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Mathematics 14 Online
OpenStudy (ashy98):

Simplify the expression

OpenStudy (ashy98):

\[\frac{ \sqrt{-25} }{ (5-2i)+(1-3i) }\]

OpenStudy (ashy98):

\[\frac{ -25+30i }{61 }\] That is the answer im getting

OpenStudy (mjdennis):

I got the same answer. Do you understand how you got there?

OpenStudy (ashy98):

the truth, no not really lol

OpenStudy (photon336):

should be -6

OpenStudy (ashy98):

\[-\frac{ 17 }{ 58 }-\frac{ i }{ 58 }\]

OpenStudy (ashy98):

?

OpenStudy (mjdennis):

@Photon336, that is a plus sign in the bottom of the original experssion and you multiplied. Why?

OpenStudy (photon336):

@mjdennis is this what you're getting for the first part? \[\frac{5i }{ (6-5i) }\]

OpenStudy (mjdennis):

@Ashy98, is this clear: \[\sqrt{-25} = 5i\]

OpenStudy (mjdennis):

@Photon336 Yes, then multiply top and bottom by the complex conjugate.

OpenStudy (photon336):

yep :) \[\frac{ 5i }{ (6-5i) }*\frac{ (6+5i) }{ (6+5i) } = \frac{ 30i+25i^{2} }{ 36-25i^{2} }\] \[\frac{ 30i-25 }{ 36+25 } = \frac{ 30i-25 }{ 61 }\]

OpenStudy (mjdennis):

@Ashy98 if @Photon336 's explanation makes sense, I'm signing off.

OpenStudy (shelbywyatt):

lol

OpenStudy (ashy98):

yes it does(: but just to make sure the answer i told yall, is right?

OpenStudy (shelbywyatt):

yeah cuz its like photons

OpenStudy (mjdennis):

Yes. it is mathematically the same as @Photon336 gave in the last answer, too. Most teachers will like the form you used, with the real part (-25) first, the the imaginary part, over a single real denominator.

OpenStudy (ashy98):

Okay well that answers my question. Thank you guys for taking your time to help me!(:

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