Simplify the expression
\[\frac{ \sqrt{-25} }{ (5-2i)+(1-3i) }\]
\[\frac{ -25+30i }{61 }\] That is the answer im getting
I got the same answer. Do you understand how you got there?
the truth, no not really lol
should be -6
\[-\frac{ 17 }{ 58 }-\frac{ i }{ 58 }\]
?
@Photon336, that is a plus sign in the bottom of the original experssion and you multiplied. Why?
@mjdennis is this what you're getting for the first part? \[\frac{5i }{ (6-5i) }\]
@Ashy98, is this clear: \[\sqrt{-25} = 5i\]
@Photon336 Yes, then multiply top and bottom by the complex conjugate.
yep :) \[\frac{ 5i }{ (6-5i) }*\frac{ (6+5i) }{ (6+5i) } = \frac{ 30i+25i^{2} }{ 36-25i^{2} }\] \[\frac{ 30i-25 }{ 36+25 } = \frac{ 30i-25 }{ 61 }\]
@Ashy98 if @Photon336 's explanation makes sense, I'm signing off.
lol
yes it does(: but just to make sure the answer i told yall, is right?
yeah cuz its like photons
Yes. it is mathematically the same as @Photon336 gave in the last answer, too. Most teachers will like the form you used, with the real part (-25) first, the the imaginary part, over a single real denominator.
Okay well that answers my question. Thank you guys for taking your time to help me!(:
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