Question

HELP PLEASE. . .
(problem in attachement)

Answer 1

\[A = \frac{ (base)(height) }{ 2}\]

They give you the base and height both to be h, and the A to be 29, so how would you plug that in?

Answer 2

I don't know. . .

Answer 3

Since they say A is 29, I replace 29 with A
And since the height and base of that triangle is 'h', I replace 'h' with base and height

Answer 4

I'm sorry but I lost you at the height and base part. . .

Answer 5

The base and height is the same as the area, but in this problem instead of giving you a number, they gave you the letter 'h'

Answer 6

ok

Answer 7

So how would that look when you plug those things into the formula?

Answer 8

I'll be right back, but remember; the A is 29 not just A. The base and height is just 'h'

Answer 9

ok so it would be 29=h^2/2??

Answer 10

Perfect!

\[29 = \frac{ h^2 }{ 2 }\]

Answer 11

So now they want us to solve for h. It's pretty much like solving for x. We have to get the h alone.

Answer 12

We could just do the opposite operations. Since it's being divided by 2, we should ______ both sides by 2

Answer 13

Multiply

Answer 14

Right

\[(29)*(2) = h^2\]

Answer 15

58=h^2?

Answer 16

Yep

Now for the last step; do you know what the opposite of squaring a number is?

Answer 17

Square root? which would get you two answers
one negative and one positive but since there can't be a negative side they will be positive

Answer 18

It shouldn't give you two answers. It should just give you one answer

\[h = \sqrt{58}\]
\[h = 7.6\]

Answer 19

So. . .
\[\sqrt{58} and -\sqrt{58}\]
I think

Answer 20

There shouldn't be a negative area, that's a calculus type thing. It should just be:

\[h = \sqrt{58}\]

Answer 21

I do have to go get my sister from work. Tag me if you need extra help. I'll be back soon

Answer 22

Thank you I got the answer ^~^