Question

can some one help me please??? i will give a medal

Answer 1

ik i have to use y-y1=m(x-x1) at somepoint but idk when exactly

Answer 2

anyone?

Answer 3

you can take any one as (x1,y1) and anyone as (x2,y2)
\[m=\frac{ y2-y1 }{ x2-x1 }\]
then \[y-y1=\frac{ y2-y1 }{ x2-x1 }\left( x-x1 \right)\]

Answer 4

if i type this out will you check my work

Answer 5

please

Answer 6

sure.

Answer 7

okay it might take a few so

Answer 8

no problem.

Answer 9

Are you here?
\[y-62=\frac{ 68.5-62 }{ 68-61.5 }\left( x-61.5 \right)\]
\[y-62=\frac{ 5.5 }{ 6.5 }\left( x-61.5 \right)\]
\[y-62=\frac{ 11 }{ 13 }\left( x-61.5 \right)\]
\[13y-806=11x-676.5\]
13y=11x+806-676.5
13y=11x+129.5
\[y=\frac{ 11 }{ 13 }x+\frac{ 129.5 }{ 13 }\]

Answer 10

is this right

Answer 11

correct
my calculation is wrong .
i wrote 5.5 ,which is wrong.

Answer 12

it should be
y-62=1(x-61.5)
so y=?

Answer 13

okay thank you @surjithayer

Answer 14

yw

Answer 15

i need help, im a little confused on the work shown

Answer 16

@agent0smith will you help me please?

Answer 17

i will type out my work one sec

Answer 18

is that right an if so whats next @agent0smith

Answer 19

oh...

Answer 20

can you explain hoow to do that then, im lost

Answer 21

so you would add 68.5 instead to both side

Answer 22

???

Answer 23

okay thank you

Answer 24

so the final answer would be y=1x-136.5

Answer 25

i mean + @agent0smith

Answer 26

oh... 0.5 @agent0smith

Answer 27

okay can you delete your responses..? @agent0smith

Answer 28

@anonymous could you too?

Answer 29

@agent0smith

Answer 30

@anonymous