Question

The inverse of a function is represented as y^-1=x^2-2 . What is the equation of the original function?

Answer 1

\[a. y=-x2/2\]
\[b. y=\sqrt{x^2-2}\]
\[c. y=x^2+2\]
\[d. y=\sqrt{x+2}\]

Answer 2

@satellite73

Answer 3

\[x=y^2-2\] solve for \(y\) in two steps

Answer 4

1) add 2 to both sides \[x+2=y^2\] then take the square root of both sides

Answer 5

got it?