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Mathematics 21 Online
OpenStudy (jellybot23):

How do you graph r^2=cos(2theta) This is a polar graph and I am so confused

OpenStudy (jellybot23):

I know what it looks like, I just want to understand how to get there

OpenStudy (loser66):

just give values for theta to find r

OpenStudy (loser66):

\(r= \pm\sqrt{cos\theta}\), right?

OpenStudy (jellybot23):

The r^2 is confusing me.

OpenStudy (loser66):

if theta =0, then \(r=\pm 1\)

OpenStudy (jellybot23):

Oh okay, so it really is the same as if you just had r, except you have a + and a - value for each one?

OpenStudy (loser66):

yup

OpenStudy (jellybot23):

Awesome! Thank you so much :)

OpenStudy (loser66):

np

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