Ask
your own question, for FREE!
Mathematics
17 Online
OpenStudy (hippoharry):
need help a$ap rocky
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (hippoharry):
OpenStudy (hippoharry):
satellite73 (satellite73):
really??
OpenStudy (hippoharry):
what?
satellite73 (satellite73):
question goes in the "bad math" file
we can still do it, but the answer will not be right, it will be what your bad math teacher wants you to say
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (hippoharry):
that makes no sense
satellite73 (satellite73):
start with \[x=\sqrt{y+2}\] and solve for \(y\) in two steps
1) square both sides, get \[x^2=y+2\] then subtract \(2\) get \[y=x^2-2\]
satellite73 (satellite73):
they want you to pick the graph of \(y=x^2-2\) which is pictured, but it is a huge mistake
OpenStudy (astrophysics):
Why full graphs
satellite73 (satellite73):
because they have no business teaching math, clearly
no matter, pick the graph of \(y=x^2-2\)
do you know which one that is?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (hippoharry):
no i dont
OpenStudy (astrophysics):
Yeah this is pretty bad, in any case maybe try plotting a \[y=x^2 \] graph by making a tables of values to get the picture
OpenStudy (astrophysics):
And then once you figure that out, the -2 is y=x^2 but starts down vertically by 2 units
OpenStudy (astrophysics):
Or you can make a table of values with y =x^2-2 either way should work haha
satellite73 (satellite73):
or pick the parabola that opens up and has a vertex of \((0,-2)\)
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!