Please help!
sorry wait one second
Its ok. Take your time :)
\[4\frac{ 1 }{ 3 } -( \frac{ 1 }{ 9 } \times \frac{ 3 }{ 4 })\]
We would first work out the fraction in the paranthesis...we would multiply across and simplify it to not make it complicated... \(\Huge{\frac{1\times 3}{9 \times 4}=?}\)
1?
Not quite. \(\Huge{\frac{1 \times 3}{9 \times 4}=\frac{3}{36}}\) We would now simplify it...we see that we can divide by `3`.... \(\Huge{\frac{3 \div 3}{36 \div 3}=\frac{1}{12}}\) Do you understand my process?
Yes i do.
Great! Now we would see on how equation looks like now... \(\Huge{4\frac{1}{3}-\frac{1}{12}}\) We would need to change the proper fraction into an improper fraction. \(\Huge{4\frac{1}{3} \rightarrow ?}\) What would be the improper form of \(\Large{4\frac{1}{3}}\)
\[\frac{ 13 }{ 3 }\]
\[\frac{ 52 }{ 12 }\]
Ooops that disappeared. Thats correct :) Now we can subtract them both... \(\Huge{\frac{52}{12}-\frac{1}{12}=\frac{?}{12}}\) What would that equal?
51/12??
Correct :) Now we would get the simplified form of the fraction by dividing by 3... \(\Huge{\frac{51 \div 3}{12 \div 3}=?}\) What would our final answer be?
17/4?
Correct :) Now \(\LARGE{\frac{17}{4} \rightarrow 4\frac{1}{4}}\) is its mixed number form.
Sorry my explanation took long.
Thank you so much! and no your totally fine i just need to get the concept.:P
I am glad to be of help :)
i have 1 more then i can let you be free from me xD
Alrighty :) you can post it here if you want I dont really care about the medals.
ok ill just post here then. and you totally deserve medals:D
:)
Two fifths of the 45 fish in the tank were guppies. (a) How many of the fish were guppies.
To solve we can multiply the total fish into the fraction... \(\Huge{\frac{45 \times 2}{5}}\)
so 45 x 2 = 90 then do i divide or would it be 90/5?
Yes you would do that :)
which one?
Sorry if I was not specific...the divide one ^^
Okay, and your fine:)
so that would be 18.
Correct :)
Thank you so much for your help!
Np :) I am glad I was of help ^^
:) okay well, i just have a few more but i'll do them so that you don't have to help me anymore!:D
plus you've also taught me how to do the process of these ones
Well if you do need help with them I can help you its no biggie :) but if you feel you can continue on your own that's alright as well ^^
Yes i can:3 thanks though
^^ ok byee good luck with your work
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