Question

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Since I don't have much experience with how to graph line that aren't directly x=6 or y=0 for example, forming the shape enclosed by the region is a bit confusing with me because of those ones that aren't directly x=8.

Answer 1

@zepdrix

Answer 2

For those two equations you can just solve for y

Answer 3

And they'll be lines

Answer 4

What do you mean?

Answer 5

Solve for y and it'll be y=5x/6 and the second will be 7-(x/3)

Answer 6

Do you know how to graph the lines with the format y=mx+b?

Answer 7

I do not.

Though, we did learn.

Perhaps give me a slight review so I remember again.

Answer 8

So y=mx+b m is the slope and b is the y intercept which is the point where you go on the y-axis

Answer 9

So the equation for one is y=-(x/3)+7 so you go up seven on the x axis and put a dot there. From there the slope is -(x/3) so that means you go down one and to the right 3 or you can also go up one and to the left 3

Answer 10

This is a bit complicated even for me but @openstudier013087 is in the right direction...

We would first change the standard-form equation into slope-intercept form equation to better graph them so....

\(\Huge{6y-5x=0}\) We would get y to itself so we would first add 5x on both sides...

\(\Huge{6y=5x+0}\) In which we would then divide by 6...

\(\Huge{y=\frac{5}{6}x}\)

~~~~~~~~~~~~~~~~

We find the other slope-intercept form equation....

\(\Huge{x+3y=21}\) We get y by itself so we subtract by x...

\(\Huge{3y=-x+21}\) In which we would divide by 3...

\(\Huge{y=-\frac{1}{3}x+7}\)

We would then graph...

Answer 11

For the area, I got 52.5. Did you get that too? @563blackghost

Answer 12

Wait sorry 21

Answer 13

The second question is a bit confusing though because I know that it's calculus and you'd have to do integration right?

Answer 14

No, I got the height 6 and the base 7