Use △DEF, shown below, to answer the question that follows: Triangle DEF where angle E is a right angle. DE measures x. DF measures 55. Angle D measures 49 degrees. What is the value of x rounded to the nearest hundredth? Type the numeric answer only in the box below. http://learn.flvs.net/webdav/assessment_images/educator_geometry_v16/0702_g1_q2.gif
please help me i need to pass geometry to graduate thanks <3
can you upload the photo because the link isn't working
here you go
@horsegirl27 let's help her together
First, welcome to OS! Second, what exactly do you need help on? I will help, however I just need to see what part you're confused by then you can learn the material rather than just the answer.
simply put i just need to understand how to find a missing side or angle. the FLVS course explains it but it kind of goes right over my head if you can give me a step by step on how to solve the problem at the top i would greatly appreciate it
I'll try my best, just bear with me as I may be a little slow at remembering how to do this. I'll try my best to explain the entire process simply
Let's start with finding a missing angle. Then I'll explain finding a missing side.
thats fine i have all night lol thanks for even trying though
we can simply find the missing angle since we know the sum of triangle is 180 degrees therefore 90+ 49 + x = 180 but not the angles is what they looking for... i believe i can use the sine function to find this.
Well first, find the angles, then find the sides.
And @Will.H I'm sure you can use the sine function to find it, but I learned it not doing that so I may drop out if that's how you'll explain it
do you know the rule that says \[\cos(anglex) = y/s\] where s is measure of the known sides and measure of angle shouldn't be the right angle measure we should add the other angle. therefore. \[\cos(49)= s/55\] and so x= 36 is that make sense? do you know that rule?
not really, what would y be in that? im sorry but youre gonna have to explain it like youre talking to a 10 year old. you might as well be
oh sorry. i might missed up with variables. i meant to add y instead of s in the last step. but not either sure of the answer. so up to you bruh
is it Cos or tan that we should add? @thenicknac
no clue.
we can use the sine function to get the answer which i know she need to understand the way not the answer. but that's what i could do. or really give me another 5 mins. it's been awhile since geometry
alright, i can wait 5 mins
@horsegirl27 i need you here
Sorry idk anything about sine functions
But I may be able to explain it a different way
What we need to use is the pythagorean theorem. Do you know what that is?
i know of it lol
the square of the hypotenuse is the other 2 sides right?
hold on a sec
So do you know that it's a^2+b^2=c^2? That's the first part of understanding it
yes
ik that much i'd hope lmao
i do now lol
Ok well good lol
so your hypotenuse on triangle DEF is 55
And so currently you have a^2+b^2=55^2
the answer is 45.51 you can use the way i used in the first place but instead of cos just put tan. that was my mistake. do you agree with this result @horsegirl27
Ummm hold on @Will.H show me your process
after all, @thenicknac does need to understand how you found that
thanks for the answer but, i would to know what im doing so i can complete the other 4 questions without bothering you
would like to**
use the Pythagorean theorem to find if that's correct by substituting one of the legs by 45.51.
Anyway @thenicknac were you still following with what I was saying? Have any of your lessons been mentioning the pythagorean theorem?
yes and im following
Ok good. So next we'll need a^2 so we can find b^2
yes, how i would i go about doing that...
Ok I know this but first let me double check google so i don't misconstrue what I've learned before lol So just give me a few minutes
alright, take your time
what Geometry course do you take? have you learned about sin, cos, tan?
Let's hope you have because that will make your life so much easier
i have a geography course through Florida Virtual School, and it did teach it but it kinda just flew over my head... Math really isnt my strong suit. i've failed my past 3 classes.
luckily i rememver a song from my geometry teacher at actual school, and that should help lol
because the question can never be found by the Pythagorean theorem. for the Pythagorean theorem there has to be at least 2 known variables. and your mission would be finding the 3rd. HOWEVER in this one, we have to missing legs (sides) so it is impossible to use the Pythagorean theorem. so this question is essentially about sin, cos, tan
Well we can use sohcahtoa to then use the pythegorean theorem can't we?
Sorry if I'm wrong here oops lol
No worries, Pythagorean theorem is no good in this question, you can use it after finding the measure of that side so that you check your answer.
How about you explain sin, cos tan, then I'll explain checking it lol so then i can explain the pythagorean theorem too just in case haha
sine is opposite/hypotenuse, cosine is adjacent/hypotenuse and tangent is opposite/adjacent right
this is the process of answering this question. i can't really explain about sin, cos, tan. because it would take me a whole day. i will give you the process and then you can analyze it. the rule we must use is tan(49) = x/55 then solve for x. that's all i can do, sorry tho.
That's simple enough, thanks
before doing your assignment just have a quick review over the module.. and @horsegirl27 you like the easy jobs? lol
i fanned you BTW
ofc i like the easy jobs @Will.H I'm half asleep lol
oh thank you sm <33
i'm not really half asleep am just about to fall. and your welcome <33
anyway @thenicknac use what Will gave you and solve for x and then I have like 2 minutes but I'll do my best to explain the pythagorean theorem
and i'll go now. wish you 2 the best. bye
thank you for the help will
i'd send you money if i could lol <3
no need give it to my friend @horsegirl27 see you later.
so with the pythagorean theorem you plug in the hypotenuse as c^2 and then your other side you have. Say you're given side a, so plug in for a^2. Then, square those sides and then get the square root of everything so your missing side (a or b) = the answer you got hopefully that made sense I can show you with an example if you need it
i would appreciate that
so say you have a right triangle XYZ remember that image i showed you with sides a b c? Let's say c, your hypotenuse is 10 and you're given side a which is 6. you need to find b. so you have a^2+b^2=c^2 6^2+b^2=10^2 36+b^2=100 b^2=100-36 b^2=64 find the square root of b^2 and 64 and you end up with b=8. So your missing side would be 8.
that actually makes perfect sense, thank you very much
Glad you understand!! You're very welcome :) Best of luck in completing the rest of your questions and passing your course
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