Question

PLEASE help with geometry q

Answer 1

@calculusxy @jhonyy9

Answer 2

Words to the wise: your phrasing could be improved as follows:

"we will need to kind of "differentiate" it from x, and then equate it to 0:"

"Differentiate f(x) and set the derivative = 0. Solving the resulting equation for x, we get x=-2." Substituting this x value into f(x), we get ... ? How would you know if that's really the minimum value of f(x) (not "for x"), and not the max value?


" g(x)= 2sin(2x-pi)+4; we then plug it into the same kind of equation as for f(x) so: y/x= 2cos(2x-pi) x 2 =0, then 2x-pi= pi/2. Thus, we get x= 3pi/ 4. "

"Differentiate g(x), obtaining 4 sin (2x-pi). Set (dg/dx) = to 0 and solve for x" Determine whether there is more than one solution on the interval [0,pi]. Determine the x value or values on that interval that result in the function g(x) having a minimum.

compare the two (or more) minimums found in this manner."

Answer 3

@mathmale is what I have complete? I didnt know what to do past what i wrote

Answer 4

@mathmale plz help

Answer 5

Basically, all you have to do now is to paraphrase what I have explained.

Focusing on the first function, with the goal of determining the minimum value of that function,. what would you do?

1. Differentiate this function with respect to x.
2. Set the resulting derivative = to 0.
3. Solve for the critical values (the values of x that make the derivative = 0)
4. And so on.

Please attempt this yourself; I would then be willing to check through your own work.

Answer 6

@mathmale