Question

Help graphing an ellipse?

Answer 1

16x^2 + 9y^2 = 144

Answer 2

@ganeshie8 @inkyvoyd could you help?

Answer 3

@zepdrix @Preetha @freckles

Answer 4

oh ellipise center is (4,3)
so sift the elipise from 0,o to 4,3

Answer 5

How do I find that center? @kky10997

Answer 6

sorry center is 16,9

Answer 7

\[\frac{ x^2 }{ a^2 } + \frac{ y^2 }{ b^2} = 1\]

Answer 8

I know I'm supposed to get it into that form, but I don't know how to

Answer 9

(x-a)^2 +(y-b)^2=c then a,b is center of elipise

Answer 10

Oh okay, well I can see that

Answer 11

@kky10997 Okay so now that I have the center, how do I graph the ellipse?

Answer 12

oh btw its a circle not elipise and its ridus is 12 and its center is 16 ,9

Answer 13

Uh no

Answer 14

(x-a)^2 +( y-b)^2=r^2 is equation of circle with center (a,b) and redius r so its not elipise .It is a circule

Answer 15

a circle is just a special type of ellipse that is equidistant from the center at all points, ellipses are just cattywompous circles

Answer 16

yeah circle is special form is elipise and it is circle

Answer 17

No...

Answer 18

I figured out the next two steps

Answer 19

ax^2+by^2=c^2 if a=b cofficent of x^2and y^2 are same then it is a circle and in (x-16)^2+(y-9)^2=144 this eqn cofficent of x^2 and y^2 is same so it circle and it is very different from 16x^2 +9y^2=144

Answer 20

This is the general form x^2/a^2 + y^2/b^2 = 1

Answer 21

I just got it into general form, so what do I do next with it?

Answer 22

See the attached file, you use a and b to draw.

Answer 23

Ohhhh

Answer 24

Can i try and graph it and can you check it in a moment?

Answer 25

sure

Answer 26

is eqn is 16x^2+9Y^2 =144 this

Answer 27

Yep looks good !

Answer 28

two of those regions are supposed to be negative I just didn't write it

Answer 29

Thanks @math&ing001

Answer 30

Anytime !

Answer 31

its for the eqn 16x^2+9y^2=144