Question in screenshot!

Question

lilkg77 · Answer

attachment

loser66 · Answer

Any idea?

agent0smith · Answer

Same question as yesterday... first start by getting x^2 alone in the first equation, by subtracting y^2 from both sides.

lilkg77 · Answer

@agent0smith Okay

agent0smith · Answer

What do you get? It shouldn't take very long.

lilkg77 · Answer

x^2 = 16 -y^2

agent0smith · Answer

Yes. Now replace the x^2 in the second equation, with that 16 - y^2

lilkg77 · Answer

16-y^2/4 - y^2/25=1

agent0smith · Answer

Use parentheses correctly, or use the equation editor.

lilkg77 · Answer

Theres no parentheses in the answer choices @agent0smith

lilkg77 · Answer

But is it correct?

agent0smith · Answer

No, I'm saying, you cannot write things in text like that, without using parentheses.

16-y^2/4 - y^2/25=1 
is NOT the same thing as
(16-y^2)/4 - y^2/25=1

If you're going to write things in text, and not the equation editor, you need to use parentheses.

lilkg77 · Answer

Oh okay thanks I didnt know that

agent0smith · Answer

16-y^2/4 - y^2/25=1 means the same as $$\Large 16-\frac{ y^2 }{4 } -\frac{ y^2 }{ 25 }=1 $$

(16-y^2)/4 - y^2/25=1 means $$\Large \frac{ 16- y^2 }{4 } -\frac{ y^2 }{ 25 }=1$$

Big difference.