Question

Can someone please help me with this math question?
Please? I will fan and give a medal!!

Answer 1

Please help me to simplify this rational expression -
(6x) (2y+2)
------ * -------
(y+1) (3)

Answer 2

@mathstudent55 do you think you could try to help me? please?

Answer 3

start by multiplying the fractions, and getting the product. Do you know how to multiply fractions?

Answer 4

why dont believ in my help ?

Answer 5

@wilsondanielle would I cross multiply? Like (6x)*(3)?

Answer 6

you cross when you divide - multiplying fractions is really easy. Multiple the top and then multiply the bottom!

eg : 3x/2 * 4/2x = 12x/4x (=3)

Answer 7

Oh ok but where did you get the 4?

Answer 8

2*2x = 4. That's an example fraction - it has nothing to do with your actual fraction.

What would the product of YOUR fraction be?

Answer 9

Oh! I was a little confused for a second!

Answer 10

no worries! once you have your product we can start simplifying, so just post it when you have it.

Answer 11

Would I do 6*2? For the top? The (2y+2) I don't understand

Answer 12

don't worry about splitting that up yet. you should wind up with something like this :

6x (2y+2)
_________
3 (y+1)

Answer 13

does that look familiar at all?

Answer 14

Somewhat, so it would be,
6x (2y+2) 12y
________ = -------------
3 (y+1) 3
?

Answer 15

close! it should be x, not y, and 12 can be divided by 3.

Answer 16

Oh ok so,
(2y+2) 12x
________ = -------------
3 (y+1) 3

12/3=4?

Answer 17

your final answer should still include an x - nothing is canceling it out.

Answer 18

Oh ok

Answer 19

So then what do we need to do?

Answer 20

just try the final simplification once more - you almost had it.

What is 12x/3?

Answer 21

12x/3=3x

Answer 22

double check 12/3. It isn't 3...

Answer 23

4x sorry I meant to put that! Thank you for correcting me!

Answer 24

yep that's perfect! good job

Answer 25

Awesome!! thank you fr being a great teacher!! you really made it easy to understand!

Answer 26

I have two more that I am having some truble with would you mind helping me with them?

Answer 27

haha thank you! I'm glad you got it. Now you can even teach someone else!

Answer 28

I can help you with them. You can make new questions, message me, or post them here. Just tag me if you post them elsewhere!

Answer 29

yes sir/ ma'am, I'll post as a new question so you can get another medal