Question

Check my solution.

Answer 1

\[(3x - 1)^2 = 5\]

Answer 2

x=13+5√3,13−5√3

Answer 3

and my answer is

\[\frac{x=1\pm \sqrt{5} }{ 3 } \]

Answer 4

x has two solutions- one being extraneous.
It is plus minus (root five-1)/3
However, only the positive answer checks

Answer 5

Yes, one is extraneous

Answer 6

Heh?

Answer 7

\[\sqrt{(3x -1)^2} = \sqrt{5}\]
\[3x - 1 = \sqrt{5}\]
\[3x = 1 \pm \sqrt{5}\]
\[x = \frac{ 1 \pm \sqrt{5} }{ 3 }\]

You're correct :) \[\huge \checkmark \]

Answer 8

Yaaas thanks sistaa<3

Answer 9

You're welcome sistaa :) <333

Answer 10

oh sorry you are correct, they both check. Usually one is extraneous

Answer 11

You're welcome

Answer 12

Thanks cx