Elimination using multiplication heeelllp 7x+4y=-4 5x+8y=28
what's the question here....
How do I solve this by elimination using multiplication
7x+4y=-4 solve for y
How though
7x+4y=-4 5x+8y=28 Multiply the first equation by 2 so that way we can eliminate y. For example if the equation is a + b = c If we multiply both sides by 2, we get: 2(a + b) = 2(c) 2a + 2b = 2c Do that for 7x+4y=-4. Multiply it by 2 on both sides
I now have 14x+4y=-8
A little mistake: Distributive property on the left side 2(7x + 4y) = 2(7x) + 2(4y) = 14x + 8y So the equation should be: 14x + 8y = -8 Do you understand? :)
Yea
So let's put this new equation next to the second equation 14x + 8y = -8 5x + 8y = 28 Now, subtract the second equation from the first 14x - 5x + 8y - 8y = -8 - 28 Simplify that further :)
Would it be -36 or 9
Custom I have 9x=-20 sorry I mentioned to say -20 instead of 9
Because not custom
-36 was correct. And so is 9 -8 - 28 That's the same thing as -1(8 + 28) = -1(36) = -36 and so now we have 9x = -36 Divide both sides by 9 to solve for x
X=4?
@TheSmartOne
-36/ 4 = ? There is a negative sign. Be careful!
Sorry forgot to put it in
No how do I find y
Now not no
@TheSmartOne
Plug in the value of x into any of the equations and solve for y. 7(-9) +4y=-4 Solve for y
Why a negative 9
Never mind
Now I have -14+4y=-4
my bad it should be -4
So it's not what I got
7(-4) +4y=-4 Solve for y
I now have -28+4y=-4
Add 28 to both sides now :)
4y=24?
Good, good! Now divide both sides by 4
Y=6?
That's correct! And so we got: x = -4 y = 6 That makes the final solution in coordinate form (-4, 6) Because coordinate form is (x, y)
Thanks do you mind helping me with 1 more please?
Sure! Since I just explained it to you, I want you to try this one on your own. Post all your work and I'll try to catch your mistakes/help you along the way :)
Well the problem is sorta different because it's 2x-4y=-22 3x+3y=30
Ah, it's not that different. We need to multiply the first equation by a certain number, and the second equation by a different number so that way we can get the same number like 6x in both the first and second equation. So, which variable do you want to eliminate?
Can we eliminate 3y
ok We have 4y in the first equation, and 3y in the second equation Can you find the least common multiply of 4 and 3?
Is it 1?
List the multiples. For example, multiples of 2 are: 2, 4, 6, 8, 10, and so on
12 right?
I forgot to put the 2 in 12 sorry
Correct 2x-4y=-22 3x+3y=30 That means we need to multiply the first equation by 3, and the second equation by 4
All of it or just the 2x-4y parts
You multiply both sides and remember a(b + c) = ab + ac a(b - c) = ab - ac
6x-12y=66? 12+12y=120?
@TheSmartOne
6x - 12y = -66 12x + 12y = 120 You forgot the - sign before 66, I've added it :P Not add both equations: 6x + 12x - 12y + 12y = -66 + 120 The y's should cancel, and simplify it more :)
BRB I have to clean
Sure!
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