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OpenStudy (volleyballlover55):
OpenStudy (volleyballlover55):
@TheSmartOne @rebeccaxhawaii
OpenStudy (volleyballlover55):
@Jakesaurus1127
OpenStudy (volleyballlover55):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
What do you have so far?
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OpenStudy (volleyballlover55):
nothing..
OpenStudy (volleyballlover55):
@jim_thompson5910 ???
jimthompson5910 (jim_thompson5910):
Have you heard of the rule that
\[\LARGE \left(x^y\right)^z = x^{y*z}\]
?
OpenStudy (volleyballlover55):
yes
jimthompson5910 (jim_thompson5910):
So we'll use this rule to break down the expression
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OpenStudy (volleyballlover55):
ok!
jimthompson5910 (jim_thompson5910):
For instance
\[\LARGE \left(3^{8}*2^{-5}*9^{0}\right)^{-2} = 3^{8*(-2)}*2^{-5*(-2)}*9^{0*(-2)}\]
Notice how the outer exponent (-2) is multiplied by EVERY exponent inside. It's kinda like distributing.
jimthompson5910 (jim_thompson5910):
make sense?
OpenStudy (volleyballlover55):
yea
jimthompson5910 (jim_thompson5910):
what is 8*(-2) equal to?
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OpenStudy (volleyballlover55):
-16
jimthompson5910 (jim_thompson5910):
how about -2*(-5) ?
OpenStudy (volleyballlover55):
10
jimthompson5910 (jim_thompson5910):
So this means
\[\Large \left(3^{8}*2^{-5}*9^{0}\right)^{-2} = 3^{8*(-2)}*2^{-5*(-2)}*9^{0*(-2)}\]
\[\Large \left(3^{8}*2^{-5}*9^{0}\right)^{-2} = 3^{-16}*2^{10}*9^{0}\]
\[\Large \left(3^{8}*2^{-5}*9^{0}\right)^{-2} = 3^{-16}*2^{10}*1\]
\[\Large \left(3^{8}*2^{-5}*9^{0}\right)^{-2} = 3^{-16}*2^{10}\]
jimthompson5910 (jim_thompson5910):
Do you agree?
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OpenStudy (volleyballlover55):
yes!
jimthompson5910 (jim_thompson5910):
ok now onto the piece
\[\Large \left(\frac{2^{-2}}{3^{3}}\right)^{4}\]
jimthompson5910 (jim_thompson5910):
The \(\Large 3^3\) in the denominator can be written as \(\Large 3^{-3}\)
In other words,
\[\Large \frac{1}{3^3} = 3^{-3}\]
do you agree?
OpenStudy (jakesaurus1127):
@volleyballlover55 the answer to your other problem was \[(3^{8}*2^{-5}*9^{0})^{-2}*(\frac{2^{-2}}{3^{3}})^{4}*3^{28}\]\[(6^{3})^{-2}*(\frac{.25}{27})^{4}*22,876,792,454,961\]\[0.0000214335*0.0092592592*22,876,792,454,961\]\[4540090.07357\] sorry it took so long.
OpenStudy (volleyballlover55):
isnt the answer 4?
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OpenStudy (volleyballlover55):
@jim_thompson5910 is he correct?
jimthompson5910 (jim_thompson5910):
do you agree with what I posted last @volleyballlover55 ?
OpenStudy (volleyballlover55):
yes..
jimthompson5910 (jim_thompson5910):
So,
\[\Large \left(\frac{2^{-2}}{3^{3}}\right)^{4}=\left(2^{-2}*3^{-3}\right)^{4}\]
jimthompson5910 (jim_thompson5910):
What do you get when you multiply the outer exponent (4) by the inner exponents?
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OpenStudy (volleyballlover55):
um, idk..
jimthompson5910 (jim_thompson5910):
first tell me what the inner exponents are
jimthompson5910 (jim_thompson5910):
any ideas @volleyballlover55 ?
OpenStudy (volleyballlover55):
um.. 531441/256
jimthompson5910 (jim_thompson5910):
I'd leave it in exponent form
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jimthompson5910 (jim_thompson5910):
example: instead of saying 1024, write 2^10
jimthompson5910 (jim_thompson5910):
do you know what I mean by "exponent form" ?
OpenStudy (volleyballlover55):
yes..
jimthompson5910 (jim_thompson5910):
Use the rule
\[\Large \left(x^y\right)^z = x^{y*z}\]
and tell me what
\[\Large \left(2^{-2}\right)^{4}\]
is equal to in exponent form
OpenStudy (volleyballlover55):
1/256
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jimthompson5910 (jim_thompson5910):
the exponents are -2 and 4. Multiply them to get -8
so
\[\Large \left(2^{-2}\right)^{4}=2^{-2*4}=2^{-8}\]
That's what I meant by "exponent form"
jimthompson5910 (jim_thompson5910):
Let's try another for practice. What is (3^5)^7 in exponent form?
OpenStudy (volleyballlover55):
can we please just get onto the problem.. i need to finish it..
jimthompson5910 (jim_thompson5910):
If you aren't going to work with me, then I can't help you. Sorry