PLEASE HELP! WILL MEDAL!
Rewrite the rational exponent as a radical.
(5^3/4)^2/3
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satellite73 (satellite73):
\[\huge b^{\frac{m}{n}}=\sqrt[n]{b^m}\]
OpenStudy (neonclawzz):
Could you help understand what i am supposed to do?
jimthompson5910 (jim_thompson5910):
@neonclawzz the first thing you need to use is this rule
\[\Large \left(x^y\right)^z = x^{y*z}\]
For example,
\[\Large \left(x^3\right)^4 = x^{3*4}=x^{12}\]
OpenStudy (neonclawzz):
I think i just got it. It's 5 squared correct?
jimthompson5910 (jim_thompson5910):
not 5 squared, but you're very close
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jimthompson5910 (jim_thompson5910):
did you mean square ROOT of 5?
OpenStudy (neonclawzz):
YES sorry!
jimthompson5910 (jim_thompson5910):
yes \(\LARGE \sqrt{5}\) is the final answer. Nice job.
jimthompson5910 (jim_thompson5910):
After using the rule I posted, you should get 1/2 as an exponent
Then we use the rule @satellite73 wrote out
\[\huge b^{\frac{m}{n}}=\sqrt[n]{b^m}\]
\[\huge 5^{\frac{1}{2}}=\sqrt[2]{5^1}\]
\[\huge 5^{\frac{1}{2}}=\sqrt[2]{5}\]
\[\huge 5^{\frac{1}{2}}=\sqrt{5}\]
OpenStudy (neonclawzz):
Thank you for the help :>
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