Question

I need help

Answer 1

this first is 13 and next is 12 and the rest is 13 right?

Answer 2

@mathmate check plz?

Answer 3

and its 4 for l

Answer 4

@jim_thompson5910 help check?

Answer 5

you got the one for Lancelot correct, but the one you got for Galahad is incorrect

Answer 6

its 11

Answer 7

a = 9
b = x-1
c = 15
Use the Pythagorean Theorem
\[\Large a^2 + b^2 = c^2\]
\[\Large 9^2 + (x-1)^2 = 15^2\]
\[\Large 81 + x^2-2x+1 = 225\]
\[\Large 81 + x^2-2x+1 - 225=0\]
\[\Large x^2-2x-143=0\]
solve for x

Answer 8

keep in mind that x > 0. Otherwise, it makes no sense to have a negative side length

Answer 9

oh okay

Answer 10

actually, the side length x-1 > 0 so x > 1

Answer 11

next?

Answer 12

I'll let you solve. Give it a shot

Answer 13

The quadratic formula is best to use

Answer 14

x=13

Answer 15

yes correct

Answer 16

so how about the others?

Answer 17

for the one with Gawain, you'll use the rule under `a Tangent and a Secant` on this link

http://www.regentsprep.org/regents/math/geometry/gp15/circleangles.htm

Answer 18

its x=34

Answer 19

no

Answer 20

show me how you got 34

Answer 21

129-61=68/2=34

Answer 22

I see, notice how the angle isn't simply x. It is (3x-5) degrees

Answer 23

so it should be 3x-5 = 34 which means x = ???

Answer 24

97

Answer 25

you made a mistake somewhere

Answer 26

Did you add 5 to both sides? Then divide both sides by 3?

Answer 27

oh its 13 my bad

Answer 28

i plugged 34 into x

Answer 29

I see

Answer 30

yes x = 13 for Gawain

Answer 31

so far, the 3 knights in the top row all have x = 13

Answer 32

yup

Answer 33

the next one is 13

Answer 34

26/2 equal 13

Answer 35

for Sir Robin, use the formula in the `Two Secants` section

http://www.regentsprep.org/regents/math/geometry/gp15/circleangles.htm

Answer 36

x = 13 is not the correct answer for Sir Robin

Answer 37

14

Answer 38

yep

Answer 39

yeah last one is 13 so its 4