Question

can someone be nice enough to help me please

Answer 1

You already have the answers it seems

Answer 2

I thought for \(a\cos(bx-c)\) phaze shift is \(\dfrac{c}{b}\) so \(\dfrac{-\pi}{1}\)?

Answer 3

yeah phase shift has to be negative here from what I can remember

Answer 4

google agrees

Answer 5

Other than that, you have done a really good job!

Answer 6

Are you stuck at graphing the curve ?

Answer 7

yes

Answer 8

Can you sketch the parent function y = cos(x) ?

Answer 9

You don't need to be precise while sketching these by free hand, give it a try...

Answer 10

It would be something like a wave