Question

Trig Question.

Answer 1

\[\frac{ 1 -2sinAcosA }{ cosAsinA } = secAcosecA + 1\]

Answer 2

how can you rewriting the secA and cosecA so try this for the first step

Answer 3

Something wrong on this question. The right hand side should be \(sec (A) csc(A) -2\)
If it is correct, then a counterexample when A =pi/4 gives you the expression is wrong.
Like this
if A =pi/4, sin A cos A = 1/2 and sec (A) csc (A) = 2
The LHS is \(\dfrac{1-1}{1/2}=0\), while the RHS is 3