Question

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Which is the equation of a 20 cm diameter circle with its center at (3, -6)?

(x+3)^2+(y-6)^2=100
(x-3)^2+(y+6)^2=400
(x-3)^2+(y+6)^2=100 9 years ago

Answer 1

here we have to apply the definition of a circumference, namely:
"it is the set of all points whose distance from the center is equal to the radius". Now using the Theorem of Pitgora, we can write such statement as follows:
\[{\left( {x - 3} \right)^2} + {\left( {y - \left( { - 6} \right)} \right)^2} = {20^2}\]

Answer 2

oops.. I have made a typo:
\[{\left( {x - 3} \right)^2} + {\left( {y - \left( { - 6} \right)} \right)^2} = {\left( {\frac{{20}}{2}} \right)^2}\]

Answer 3

so, your answer is correct!