Question

HELP PLEASE:

Answer 1

@phi I am really stuck on this one

Answer 2

really need help on this one

Answer 3

i think it is choice A, but Im not 1000% sure

Answer 4

1. First convert the table to overall probabilities:
Add up all four numbers, call it total.
Divide each entry by the total to give the probability of each of four cells.
Make sure the sum of probabilities add up to one.

Can you do that?

Answer 5

you could do that. you could also do this:
P(female | type B)

which means "Prob if female given type B"
circle just "type B" row
then find the ratio of female to total in that row

Answer 6

@mathmate

Answer 7

P(female|type B) = P(female \(\cap\) type B) / P(type B).
If you did step 1 above, you can find easily P(female \(\cap\) type B) and P(type B).
P(female \(\cup\) type B) = P(female)+P(type B) -P(female \(\cap\) type B)

P(female \(\cap\) type B) is the entry (from step 1) where the column type B meets the row female.
P(type B) is the sum of the two entries on col. type B
P(female) is the sum of the two entries on row female.

Answer 8

or?

Answer 9

hello?

Answer 10

Sorry, I do not know, I have not worked it out.
If you show me your work, I will tell you if the answer is correct.

Answer 11

well I already showed my work with the probabilities, and then with that I concluded with choice A, but I am not sure i said

Answer 12

so I don know what to do exactly

Answer 13

hello? could you please reply/...

Answer 14

hello?

Answer 15

@phi can i have help please?

Answer 16

@phi

Answer 17

i can help you!

Answer 18

@iwanttogotostanford you there? :)

Answer 19

yes! @volleyballlover55 sorry please do help!

Answer 20

I really need help here people, did I get it right- is it choice A???

Answer 21

To do the comparison, you need to calculate P(female \(cup\) type B).
I have shown above how you can get that.

Answer 22

***
so for female the probability would be: for Type A: 85/150 and for Type B:12/50 ?
***
those are the correct numbers, but you should say Pr( female | type A)
and Prob(female | type B)
we want the 2nd , 12/50 or 24/100 or 24%

we also need Pr(female OR type B)

Answer 23

Prob of female or B is the sum of the numbers in either category
divided by the total in all of the boxes

Answer 24

Is it just me or everyone, OS is going resetting almost every time I start typing!

Answer 25

OS has been flakey. I don't think math mate abandoned you on purpose

Answer 26

ok, me too thats what happens sometimes I guess.

Answer 27

I have always been on and trying to help!

Answer 28

ok, sorry it looked like you went away

Answer 29

So, I converted the table into probabilities but I'm still a little confused on what to do next

Answer 30

You need to find both P(female|type B) [which you already calculated with @phi 's helped], and \(P(female\cup type B)\), for which @phi and I also showed you how to get.
Once you have calculated both, the answer would be obvious.

Answer 31

so P(female | type B) would be 24% and then the other would be using what fractions? Im sorry I still don't get how to calculate the second done, which fractions (probabities) would i want to use?

Answer 32

As @phi said, you add up all numbers associated with female OR type B, and divide by the total of all numbers to get the probability \(P(female\cup type B)\).

Answer 33

all of the numbers associated with female and type B would be: 85, 12, and 38 correct?

Answer 34

Yes, that's the meaning of "or".
To find the probability, you need to divide the sum by the total of all outcomes.

Answer 35

After that, you can do the comparison and find the right answer.
Hope that solves your problem.
gtg, will be back later in the evening.

Answer 36

@campbell_st @jhonyy9 do you guys agree that it is Option A?

Answer 37

I got that but the person left before they could confirm

Answer 38

I do not know if you have done the appropriate calculations, the purpose of which is to enable you to solve related problems in the future.
To help you confirm, however, P(female\(\cup\)type B) is 0.675.
The process would have been done in 15 minutes instead of an hour if OS wasn't going up and down. Sigh!