Question

help with 2 problems?

Answer 1

Sure. #24 first. You know cosine = (x/r) for the 'standard position', right?
How do they define secant and cosecant?

Answer 2

For 24. I did the work already and got B.

Answer 3

\[\csc \theta =\frac{ 5 }{ 4 }, \sec \theta=\frac{ 5 }{ 3 }\]

Answer 4

@mjdennis am I right, or no?

Answer 5

You are right on B.

Oh. What have you done on 25? I'll get caught up in a minute

Answer 6

MMhm nothing so far I dont know where to start. Guide me?

Answer 7

OK, it's like a jigsaw. We know they are 'sine functions' right? Even if it it cosine, there is an identity that turns cosine into sine, so we'll start with the most generic sine function:
f(theta) = A1*sin(b1*theta + phase1)
g(theta) = A2*sin(b2*theta + phase2)

start with f(0) = 0 and g(0) = 0 to find phase1 and phase2

Answer 8

If this doesnt sound dumb, may I ask how do we do that.. lol I suck at these.

Answer 9

But that is OK, we can skip that part here.