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Mathematics 13 Online
OpenStudy (narissa):

help

OpenStudy (narissa):

OpenStudy (narissa):

@AloneS

alones (alones):

wait which one u chose?

OpenStudy (mathmate):

When it says x^2=256. you can take the square-root on both sides and get the solution.

OpenStudy (narissa):

im confused

OpenStudy (narissa):

so its b @mathmate ?

alones (alones):

Yes.

OpenStudy (mathmate):

Yes, that's correct. Next step?

OpenStudy (mathmate):

@narissa In case you're not used to it, the next step is to check your answer. How? By putting the solution(s) back into the equation and see if it works. Here, we have x^2=(+16)^2=256 x^2=(-16)^2=(-1)^2*(16)^2=256 So yes, +16 and -16 are the solutions. Note also: A second degree equation (e.g. x^2) has a maximum of 2 (real) solutions. So that also gives another check.

OpenStudy (narissa):

thanks

OpenStudy (mathmate):

You're welcome! :)

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