Question

Show that arg(-1)=π

Answer 1

arg(-1) ?

Answer 2

The complex argument of -1?

Answer 3

For @jdoe0001 , and a hint for @daniel.ohearn1
For any complex number z (and real numbers are complex numbers with 0 for the imaginary part), we can write them in two forms: z = x + iy, or z = |z|e^(iΘ) . Theta, Θ, is also known as 'the complex argument of z', or arg(z)

z = |z|e^(iΘ) is also written, for engineers at least, z = |z|angle(Θ)

I'll add a diagram to clarify.

Answer 4

probably you want to figure
\[ e^{i x} = \cos(x) + i \sin(x) \]
and you wan that to be -1

Answer 5

or you can plot -1