HELP PLEA
@jim_thompson5910
The first thing I would do is factor out x f(x) = 9x^3 + 18 x^2 - 135x f(x) = x(9x^2 + 18x - 135)
now use the quadratic formula to solve 9x^2 + 18x - 135 = 0
after dividing all by 9 to make your life easier
true, I didn't realize that 9 was also part of the GCF
f(x) = 9x^3 + 18 x^2 - 135x f(x) = 9x(x^2 + 2x - 15) now solve x^2 + 2x - 15 = 0
can you write out the general steps for me in how to solve these kinds of problems; not necessarily with this one but for any of these problems just so i can have a general reference?
is it just : 1.) factor out x 2.) use quadratic formula?
in this case, you can factor out 9x
inmost cases can i do that?
f(x) = 9x^3 + 18 x^2 - 135x f(x) = 9x(x^2 + 2x - 15) ... factor out the GCF 9x set each factor equal to 0 and solve 9x = 0 leads to x = ??? x^2 + 2x - 15 = 0 leads to x = ??? or x = ??? use the quadratic formula to solve the equation x^2 + 2x - 15 = 0
There are several different approaches to solving quadratic equations. You'd benefit by making a list and learning how to apply each one: quadratic formula factoring factoring by grouping completing the square graphing and so on ... there are others. In this case, regard yourself lucky that 9x can be factored out; no, in general, you will not be that fortunate.
its -b + or - squarroot b^2-4ac/2a
but i don't have a calculator with me currently.
yes \[\Large x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\] is the quadratic formula use this as a calculator if you don't have one http://web2.0calc.com/
ok thanks ill calculate it real quick
I got 3.8 and -7.8
@jim_thompson5910
or 3 and -5
you should get two whole numbers
solving x^2 + 2x - 15 = 0 for x gives x = 3 or x = -5
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