Question

Write an equation of a line perpendicular to line QR in slope intercept form that contains point (5,6)

Answer 1

I assume the equation is y = (-1/2)x + 1. This equation is in the standard slope-intercept form:



y = mx + b



Where m is the slope of the line and b is the y-intercept. In your equation, m = -1/2 and b= 1.



The slope of a line perpendicular to line QR will have a slope of -(1/m) = -1/(-1/2) = 2. So the equation of the line perpendicular to line QR is:



y = 2x + b



To find b, insert the point (5,6) that the line contains as defined in the problem statement and solve for b:



y = 2x + b

6 = 2(5) + b [Insert x=5, y=6]

6 = 10 + b

-4 = b [Subtract 10 from both sides



So the final equation for the line perpendicular to line QR is:



y = 2x - 4

Answer 2

okay?

Answer 3

Yes thank you