A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation y=0.8x^2+12x+25.8 where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground.

Question

pleasehelpme888 · Answer

How far horizontally from its starting point will the rocket land? Round your answer to the nearest hundredth meter.

pleasehelpme888 · Answer

A) 25.80 m
B) 37.00 m
C) 17.24 m
D) 16.91 m

aveline · Answer

I think you wrote the equation incorrectly. Shouldn't it be negative? If not, the rocket goes into infinity and beyond.

pleasehelpme888 · Answer

Oh thank you...It is negative.

pleasehelpme888 · Answer

y=-0.8x^2+12x+25.8

aveline · Answer

In that case, where does y=0? https://www.desmos.com/calculator/ziwjnsuhpi

pleasehelpme888 · Answer

Im not sure. I didn't do well on this. I really need someone to explain it to me better.

pleasehelpme888 · Answer

Sorry I gtg....Can you explain it and ill just try to do it from there

aveline · Answer

Well it's easiest if you graph it. You can also use an equation. Just set y to 0 and use the quadratic formula.