Question

Find the 20th term of the following sequence.

-6, -4, -2, 0, ...

32
44
46

Answer 1

I feel like it should be 24 but that's not an option. What am I missing?

Answer 2

You're counting by twos. -6, -4, -2, 0, 2, 4, 6, 8....

Answer 3

What would be the twentieth number in that line?

Answer 4

So then wouldnt the 20th term be 16? Which also isn't' an option

Answer 5

-6, -4, -2, 0, 2, 4, 6, 8, 10, 12, 14, 16.... Is that 20 numbers?

Answer 6

ahhh 32!! Thank you - i should have written it down for a visual

Answer 7

What is the formula to figure this out?

Answer 8

Whoops.
\[20\times2-8\]

Answer 9

>-<

Answer 10

why minus 8?

Answer 11

Because \[-6+-4+-2+0>1\]

Answer 12

OK thanks!

Answer 13

Each one has a difference of two, meaning they are four irrelevant twos. Your 20th digit will not include them. No problem!

Answer 14

It looks like you are doubling the term number and then subtracting by 6 with n starting at 0.
2n-6
(2(0)-6)=-6 for n=0 first term
(2(1)-6)= -4 for n=1 second term
(2(2)-6) = -2 for n=2 third term
(2(3)-6)= 0 for n-3 4th term
you can keep on adding 2 to the previous term until you have the 20th term (which would be n=19 since we started at n=0) or use the equation we intuited
2n-6 = (2(19)-6) = 38-6 = 32

Answer 15

Thank you!