Question

How do you integrate this?

Answer 1

\[\int\limits_{}^{}\frac{ dt }{ 2t^2 + 3t +1 }\]

Answer 2

well, just transform the equation to
\[\int\limits_{?}^{?}2t^{-2}+3t^{-1}+1 dt\]
does this make it easier to solve it?

Answer 3

hehe yes

Answer 4

but when I integrate 3t^-1 I get zero...

Answer 5

basic rule of integration, remember this. integral of 1/x = ln(x)

Answer 6

can I just use u substitution?

Answer 7

@kelvin8262

Answer 8

u = 2t^2+3t+1
du= 4t+3 dt

du-4t-3 = dt

?

Answer 9

well, due to simplicity of this, i won't recommend you to do it this way, consider that's directly integration is a easier way.

Answer 10

so -2t^-1 + 3ln|t|+t?

Answer 11

yep. but don't forget the constant, C after integration.

Answer 12

oh ok so that's it ? :D