A field test for a new exam was given to randomly selected seniors. The exams were graded, and the sample mean and sample standard deviation were calculated. Based on the results, the exam creator claims that on the same exam, nine times out of ten, seniors will have an average score within 5% of 75%. Is the confidence interval at 90%, 95%, or 99%? What is the margin of error? Calculate the confidence interval and explain what it means in terms of the situation.
@Vocaloid Please help!
@ganeshie8 Can you help please?
How much percentage is 9 out of 10 ?
90%
Yes So that would be the confidence interval
ok, what about the margin of error?
Simply find 5 percent of 75
5% times 75?
Yes
so 3.75?
Looks good That is the margin of error
ok, finally what is the confidence interval and can you explain it in the terms of this situation please?
As the name says it us an interval. To get the lower value, subtract margin of error from 75 To get the upper value, add margin of error to 75
Ohhhhhh. I forgot! Then how do you explain this in the situation?
Could you tell me the confidence interval first
sure it is 71.25-78.75
Yep
how do you explain this in the situation?
Here is the explanation : If you take many samples and calculate the average value, we can say that 90 percent of those samples will have average value between 71.25 and 78.75
This has helped me alot. Thank you, if i have another question later can you help me?
I'll try You're welcome
Thank you! Your a lifesaver!!!
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