Question

help

Answer 1

Compare rates of change.
A. The equation below can be used to find the length of a foot or forearm when you know one or the other.

(length of the foot) = 0.860 • (length of the forearm) + 3.302

If you let y = length of the foot and x = length of the forearm, this equation can be simplified to
y = 0.860x + 3.302.

Using this equation, how long would the foot of a person be if his forearm was 17 inches long?

B. What is the rate of change of the equation from Part A?

Compare the equation from Part A to your data. Are they the same? Which has a greater rate of change? Why do you think the values are different?

C. Is the relation in your data a function? Why or why not? Could the equation in Part A represent a function? Why or why not? Explain your answer.

Answer 2

@Michele_Laino

Answer 3

hint:
for part A, we have to substitute \(x=17\). Please try!

Answer 4

\(y = 0.860 \cdot 17 + 3.302=...?\)

Answer 5

A = 17.922

Answer 6

yea, i already got A.. :)

Answer 7

correct! @ChrisHogan

Answer 8

and B?

Answer 9

You can use this to find the rate of change.
Rate of change = change in y/change in x

Answer 10

would it be easier if i told you like my whole assignment so you understand it better? theres 3 parts to the assignment , and this is the last one.. :) because for part c you need to know part of the other assignment ::)

Answer 11

for part B, we have this:
\[\begin{gathered}
r = \frac{{y\left( {{x_2}} \right) - y\left( {{x_1}} \right)}}{{{x_2} - {x_1}}} = \hfill \\
\hfill \\
= \frac{{\left( {0.860 \cdot {x_2} + 3.302} \right) - \left( {0.860 \cdot {x_1} + 3.302} \right)}}{{{x_2} - {x_1}}} = ...? \hfill \\
\end{gathered} \]
wherein \(r\) is the \(rate\;of\;change\). Please simplify

Answer 12

@Michele_Laino ok,
is this correct?
y=mx+b
m=slope
rate of change is 0.860 inches per length of forearm.

Answer 13

correct!

Answer 14

part C
hint:
every linear equation is a function

Answer 15

ok! now for this question, Compare the equation from Part A to your data. Are they the same? Which has a greater rate of change? Why do you think the values are different?
you need to know the data in order to answer it..

Answer 16

yes! I think some data are missing

Answer 17

ok i will show you the rest of my assignment, :)

Answer 18

Part 1:
You will need to measure five different people. Record your measurements on a piece of paper. Using a tape measure or ruler, measure the length (in inches) of a person’s left foot and then measure the length (in inches) of that same person’s forearm (between their wrist and elbow). Refer to the diagrams below. You will have two measurements for each person.
1- Left foot : 9.3 in Forearm : 8 in
2- Left foot : 9.5 in Forearm : 7 in
3- Left foot : 9.6 in Forearm : 7.5 in
4- Left foot : 10.3 in Forearm : 9 in
5- Left foot : 10.5 in Forearm : 10 in

Answer 19

Part 2:
Organize your data and find the rate of change.
A. Create a table of the measurements for your data. Label the forearm measurements as your input and the foot measurements as your output.

B. Select two sets of points and find the rate of change for your data.
8 and 9.3 , 9 and 10.3 .
10.3 - 9.3 / 9-8 = 1/1
So the rate of change is 1.
C. Describe your results. If you had to express this relation as a verbal statement, how would you describe it?
Relation, as x increases by 1, y increases by 1 as well.

Answer 20

there you go! thats part 1and 2 of the assignment!! :)

Answer 21

@Michele_Laino ?

Answer 22

you have to make some measurements first

Answer 23

I think that data you provided are an example

Answer 24

please note that \(...You\; will\; have\; two\; measurements \; for\; each \;person.
\)

Answer 25

i know i did :)

Answer 26

the left foot and their forearm

Answer 27

1- Left foot : 9.3 in Forearm : 8 in
2- Left foot : 9.5 in Forearm : 7 in
3- Left foot : 9.6 in Forearm : 7.5 in
4- Left foot : 10.3 in Forearm : 9 in
5- Left foot : 10.5 in Forearm : 10 in

Answer 28

we have to have \(ten\) measurements

Answer 29

we do!!

Answer 30

ok!

Answer 31

can you see it now? lol

Answer 32

yes!
if such measures are your measures, then part A is answered, since we already have the table

Answer 33

right, but it asks to answer this question,
Compare the equation from Part A to your data. Are they the same? Which has a greater rate of change? Why do you think the values are different?

Answer 34

I think that it is necessary to substitute the values \(x=7-7.5-8-9-10\) into the previous equation, and the values so obtained has to be compared with the corresponding values from the table.

Answer 35

is that the answer?

Answer 36

so, you have to compute these quantities:
\[\begin{gathered}
y = 0.860 \cdot 7 + 3.302 = ...? \hfill \\
y = 0.860 \cdot 7.5 + 3.302 = ...? \hfill \\
y = 0.860 \cdot 8 + 3.302 = ...? \hfill \\
y = 0.860 \cdot 9 + 3.302 = ...? \hfill \\
y = 0.860 \cdot 10 + 3.302 = ...? \hfill \\
\end{gathered} \]

Answer 37

oh ok...

y= 0.860 * 7 + 3.302 = 9.322
y= 0.860 * 7.5 + 3.302 = 9.752
y= 0.860 * 8 + 3.302 = 10.182
y= 0.860 * 9 + 3.302 = 11.042
y= 0.860 * 10 + 3.302 = 11.902

Answer 38

so we get this table: