Solve the equation. If necessary, round your answer to the nearest tenth. x2 = 256 A. 128 B. 128, –128 C. 16, –16 D. 16
I am guessing this is x^2 and not 2x. sqrtx^2 = sqrt256 x = 16.
BUT it can be both negative and positive, so C.
ya i meant to make it the 2 an exponent
Solve the equation. If necessary, round your answer to the nearest tenth. 4x2 = 81 A. 2.25, –2.25 B. 4.5, –4.5 C. 9, –9 D. 20.25, –20.25
\[4x^{2}=81\]
First, for your second one, try dividing both sides by 4. what do you get? (imma let you try to do this one on ur own.)
i got 20.25
good. Now, square root both sides again. You should get--- x = ? Find ?
4.5?
yes! Great job! but it can be both negative or positive, so C. again.
I meant B. :P
need any more help?
ya
Ok, shoot
What is the value of x? Round your answer to the nearest tenth. x^2 = 112
Easy! do the same as the first one, sqrt both sides. What do you get?
10.583005244258362362006463014557 this is what i got...
Ok so now round it up. 8 is greater than 5, so it becomes 10.6
but wouldn't you round in the tenths place instead of the hundredths place
and no it's not is it greater than the number before it. if you have at least .5 behind a number, you round it up. For example: 6.26 because 6 is greater than 5, you round it up to 6.3
10.6 is the tenths place. x = a number. .x = tenths .xx = hundredths .xxx = thousandths and so on.
oh that makes sense lol
Hope I helped!
If you ever need help just tag me. y'know with the @ thing.
ya can you help me with 1 more?
\[4y^{2}+8=264\]
what is y?
can you make a new post?
ya
Sorry I was AFK for a sec. @errinss make the X all by itself. by that I mean subtract 8 from both sides. Thus, you get 4y^2 = 256 Divide both sides by 4, then square root both sides of the new equation. you should get y = 8.
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