Question

given tan0=4/3 and sin(-4/5) find cos 0

Answer 1

I assume you mean

given \(\tan(\theta)=\frac{4}{3}\) and \(\sin(\theta)=\frac{-4}{5}\) find \(cos(\theta)\)

Answer 2

yes

Answer 3

so you need a quadrant where tan is positive and sin is negative

you have also been given the 3 sides of a right triangle

Answer 4

A. 1/3
B. -1/3
C. 3/5
D. -3/5

Answer 5

@.Sam.

Answer 6

@SnuggieLad

Answer 7

\[\tan(\theta)=\frac{\sin(\theta)}{\cos(\theta)}\]

\[\cos(\theta)=\frac{\sin(\theta)}{\tan(\theta)}\]

Answer 8

Set up a triangle using the given ratios

sin = opp/hyp
tan = opp/adj



cos = adj/hyp = -3/5