Question

Can you help me find the period and amplitude?

Answer 1

The periodic function is y=-4 cos 8x

Answer 2

\[y = \pm A \cos (Bx)\]
\[A = Amplitude\]
\[Period = \frac{2\pi}{B}\]

Answer 3

so amplitude would be 4 and period is 2pi/8

Answer 4

idk how to evaluate pi can you help me simplify the period

Answer 5

actually i think i might know, is it 2 times 3.14 / 8

Answer 6

For both

\(y = a \sin bx\)

and

\(y = a \cos bx\)

Amplitude: \(|a|\)

Period: \(\dfrac{2 \pi}{|b|}\)

Answer 7

okay so all you have to do is 2 * 3.14/8 for the period?

Answer 8

is it 1/4

Answer 9

Don't use 3.14 for pi.
Leave pi as pi.

Answer 10

how do you simplify it then?

Answer 11

Amplitude = |a| = |-4| = 4
You are correct with the amplitude.

Answer 12

Now let's look at the period.

Answer 13

so the period is either 1/4 or 1/4 pi

Answer 14

Period = \(\dfrac{2\pi}{|b|} = \dfrac{2\pi}{|8|} = \dfrac{2 \pi}{8} = \dfrac{\pi}{4} \)

Answer 15

1/4 pi is correct since it's the same as pi/4

Answer 16

okay thank you

Answer 17

yw