Question

Will someone help? I'm am clueless on where to start. Pics included. I WILL FAN AND MEDAL!!

Answer 1

are you familiar with sin, cos, and tan ratios (SOHCAHTOA)?

Answer 2

Yes

Answer 3

OK, so you're given angle x and the hypotenuse, and you're trying to find the side adjacent to angle x, which trig function would you use?

Answer 4

tan

Answer 5

no. you have the hypotenuse and want to find the adjacent. which one uses hypotenuse and adjacent?
\[\sin x° = \frac{ opposite }{ hypotenuse }\]
\[\cos x° = \frac{ adjacent}{ hypotenuse }\]
\[\tan x° = \frac{ opposite }{ adjacent}\]

Answer 6

oh sin

Answer 7

no
cos x° = adjacent/hypotenuse
your hypotenuse is y, so the equation is
cos x° = adj/y

Answer 8

oh

Answer 9

that's the equation you'd use to solve for the missing distance

Answer 10

sorry to ask but can you explain why cause im confused

Answer 11

segment BC at the top of the triangle is what you're looking for. That side is adjacent to angle x. You're also given the hypotenuse as y. Out of sin, cos, and tan, the ratio that has both hypotenuse and adjacent is cos. So you write\[\cos x°=\frac{ adjacent }{ hypotenuse }\]\[\cos x°=\frac{ BC }{ y }\] The only thing you don't know in this equation is BC

Answer 12

ohhh ok

Answer 13

@peachpi do you have any ideas for what to write?

Answer 14

Is this good?

Answer 15

@nikki_skellington @baozipotato97 Do you guys think it is a good answer or is it wrong?

Answer 16

Thank you for tagging me, but I honestly don't know... I'm stumped -_- sorry! Good Luck!

Answer 17

ok thanks anyways @baozipotato97

Answer 18

yes that looks good @DivinexxChocolatexx

Answer 19

@peachpi Thanks so much!