Question

State

Answer 1

@jim_thompson5910

Answer 2

set the denominator x^2 - 4 equal to 0 and solve for x

Answer 3

i don't know how to do that:-(

Answer 4

hint: x^2 - 4 factors to (x-2)(x+2)

Answer 5

(x-2)(x+2) = 0 breaks down into

x-2 = 0
OR
x+2 = 0

solve each for x

Answer 6

can you do this one like the others before, I'm not being lazy but really that helps me learn the best when i see the whole process as a whole first

Answer 7

you should give it a shot

Answer 8

it's ok to get it wrong

Answer 9

ok hold on ill try

Answer 10

so x=2 andx=-2

Answer 11

Here's a similar example


Let's say the denominator was x^2 - 9. Set it equal to 0 and solve for x

x^2 - 9 = 0
(x-3)(x+3) = 0
x-3 = 0 or x+3 = 0
x = 3 or x = -3


So the vertical asymptotes in this example are x = 3 or x = -3. This is not the answer to your question

Answer 12

`so x=2 andx=-2`
yes those are the correct answers to your problem

Answer 13

ah wow that was quite simple thanks! Promise, one more? And then I'm done haha!

Answer 14

go ahead