Question

Anybody feel like doing a related rates problem?

Answer 1

So a^2+b^2=c^2

I have da/dt but need db/dt while c is constant

Answer 2

So ill use the pythagorean thorum to get my missing values then take the derivative of the area formula to solve for dA/dT

Answer 3

But everytime I do this I do something incorrectly

Answer 4

show what you get

Answer 5

what is \(b\)? what is \(\frac{db}{dt}\)?

Answer 6

one moment

Answer 7

So first what is your equation for the area?

Answer 8

Sorry x should be dB/dT

Answer 9

\[\frac{d}{dt}[c^2]=0\]

Answer 10

ah

Answer 11

after finding the function dA/dt, you'll then plug in x = 15

Answer 12

correct

Answer 13

Thank you sir

Answer 14

I'm getting 119/4 as well. Nice job