he table shows the outputs y for different inputs x:
Input
(x) 5 6 7 8
Output
(y) 2 5 8 11
Part A: Do the data in this table represent a function? Justify your answer. (3 points)
Part B: Compare the data in the table with the relation f(x) = 2x + 13. Which relation has a greater value when x = 7? (2 points)
Part C: Using the relation in Part B, what is the value of x if f(x) = 75? (5 points)
Help Please will give medal
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Mehek (mehek14):
Use the slope formula for part A
\(\dfrac{6-5}{5-2}\)
OpenStudy (babycease):
you get 1/2
Mehek (mehek14):
Not 1/2
Mehek (mehek14):
5-2 = ?
OpenStudy (babycease):
so sorry three
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OpenStudy (babycease):
1/3
Mehek (mehek14):
My bad
Flip it
so it would be 3
Mehek (mehek14):
Should be \(\dfrac{5-2}{6-5}\)
Mehek (mehek14):
Next 2 ordered pairs
\(\dfrac{11-8}{8-7}=?\)
OpenStudy (babycease):
3/1
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Mehek (mehek14):
so both are 3
that's a function
Mehek (mehek14):
So for Part A put this:
Yes it is a function because the rate of change is 3
Mehek (mehek14):
For part B, put 7 instead of x
f(7) = 2 * 7 + 13 = ?
OpenStudy (babycease):
okay thank you im understanding better
OpenStudy (babycease):
the answer would be 27
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Mehek (mehek14):
Ok so when x = 7, y = 27
in the other function, when x = 7, y = 8
Mehek (mehek14):
Which one is greater when x = 7?
OpenStudy (babycease):
um i suppose when y is 27
Mehek (mehek14):
Correct :)
Mehek (mehek14):
So for Part B put:
the relation f(x) = 2x + 13 is greater when x = 7
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OpenStudy (babycease):
okay last one
Mehek (mehek14):
For that, we put 75 instead of f(x) and solve for x
75 = 2x + 13
Mehek (mehek14):
Any idea how to solve?
OpenStudy (babycease):
um get x by itself
Mehek (mehek14):
Yes
How would we do that?
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OpenStudy (babycease):
Not sure tbh i think subtract 75 and 13
Mehek (mehek14):
good
75 - 13 = ?
OpenStudy (babycease):
is 62
Mehek (mehek14):
Yep
now divide by 2
OpenStudy (babycease):
31
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