Question

which restriction is appropriate for the variable 3y^2-3y/y+1

Answer 1

@sammixboo

Answer 2

what can you not divide by in this equation, or in any equation

Answer 3

well it depends on the restrictions you have been taught about

are if you factor the numerator

\[\frac{3y^2 - 3y}{y + 1} = \frac{3(y -1)(y + 1)}{(y + 1)}\]

the the graph doesn't have a vertical asymptote which is a discontinuity

expression only had a point of discontinuity...

and discontinuities occur when the denominator is zero... so find the value of y that makes the denominator zero

Answer 4

@campbell_st it's just an expression, not a function, so it's only asking about the restriction for the denominator.