A jar of jellybeans contains seven red, two orange and three green jellybeans. One is selected and replaced, and then, another is selected. Find the probability that
a. The first jellybean is orange and the second is green

Question

A jar of jellybeans contains seven red, two orange and three green jellybeans. One is selected and replaced, and then, another is selected. Find the probability that
a. The first jellybean is orange and the second is green

pphalke · Answer

@jabez177 @sammixboo @smartnerd1111

pphalke · Answer

@Hero @Preetha

robtobey2 · Answer

$$\frac{2\ 3}{12\ 12}=\frac{1}{24} $$

robtobey2 · Answer

The answer is the product of 2/12 and 3/12 .

robtobey2 · Answer

There are 2 ways and 3 ways to draw an orange and a green jellybean respectively.

pphalke · Answer

the answer is 6 /144

robtobey2 · Answer

Yes.
My first major blunder since I have been a contributor on this site.
Thank you pphalke.