Will Medal, really need help please!?
Laura has 3 eye doctors, Dr. #1, Dr. #2, and Dr. #3. The probability that the Dr. #1 give the correct diagnosis is 0.89, for Dr. #2 it is 0.72, and for Dr. #3 it is 0.93. What is the probability that all 3 make an incorrect diagnosis on a given day?
do you know how to find probability
I only know that the probability of getting it wrong is 11/100; 28/100; and 7/100 respectively.
https://www.easycalculation.com/statistics/probability.php use this calculator and try to plug the numbers in name it Doctors
I dont know how to use such a calculator
What is the probability of Dr 1 being wrong? Same for Dr 2? Same for Dr 3? Multiply those three numbers.
0.2156% chance of getting it wrong?
Idk. Show your work.
(11/100)*(7/100)*(28/100)
Yep.
Ok, so there is two more parts to the question if you can help me with those then I will be fine, is that good with you?
Post them
Using the same information above, what is the probability that Dr. #2 makes an incorrect diagnosis on 3 consecutive visits
would it just be ((28/100)^3)?
Yep
Ok now here is a new problem
Post a new question for a new problem
A small bag contains 6 pennies, 5 nickels, 3 dimes, 5 quarters, and 2 one dollar coins. You choose a coin at random, do not replace it, and then choose a second coin at random. What is the probability that you chose a quarter followed by another quarter.
Is the answer (5/21)*(4/20)?
which equals (1/21)
Yes
all right we are almost done, last couple
Post a new question for them. Open a new one.
k, will you come back and help though?
Yes
thanks man, you're the best
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