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Mathematics 15 Online
OpenStudy (abbycross167):

can someone please help me with this math question? please? I'll fan and give a medal... please show me how to graph -1/2 + (1/2)y >= x

OpenStudy (kgrendel0324):

alright, im sure i remember how to do this.

OpenStudy (abbycross167):

okay, thank you!!!

OpenStudy (kgrendel0324):

now you have 3y > 2x - 1, you want to get y by itself

OpenStudy (kgrendel0324):

divide three from both sides and you get y<2/3x -1/3

OpenStudy (kgrendel0324):

OpenStudy (abbycross167):

okay what do I do next?

OpenStudy (kgrendel0324):

well thats the graph completed right there. what do you need?

OpenStudy (abbycross167):

I need all of the steps... I want to know the steps for this that way I can try to learn how to do it

OpenStudy (kgrendel0324):

okay

OpenStudy (kgrendel0324):

well there are multiple way to graph this. you want a table?

OpenStudy (kgrendel0324):

or an actual graph

OpenStudy (kgrendel0324):

nvm that im going ot assume its a graph you want.

OpenStudy (kgrendel0324):

so you want to turn this equation 3y > 2x - 1 into slope-intercept form

OpenStudy (abbycross167):

umm well I guess a ghaph? But could you explain the steps ? please?

OpenStudy (kgrendel0324):

yeah

OpenStudy (kgrendel0324):

so when you put this 3y > 2x - 1 in slope-int form you get y>2/3x-1/3

OpenStudy (kgrendel0324):

do you understand that?

OpenStudy (kgrendel0324):

or how you do that?

OpenStudy (abbycross167):

ma'am/sir I want to graph -1/2 + (1/2)y >= x ....

OpenStudy (kgrendel0324):

oh.... my bad.. idk what i was looking at...

OpenStudy (abbycross167):

its okay, would you still be able to help me?

OpenStudy (kgrendel0324):

hold on, i have to look at this one

OpenStudy (abbycross167):

okay

OpenStudy (kgrendel0324):

idk

OpenStudy (kgrendel0324):

im srry

OpenStudy (abbycross167):

okay, thank you very much for trying

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