Mathematics
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OpenStudy (abbycross167):
can someone please help me with this math question? please? I'll fan and give a medal...
please show me how to graph
-1/2 + (1/2)y >= x
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OpenStudy (kgrendel0324):
alright, im sure i remember how to do this.
OpenStudy (abbycross167):
okay, thank you!!!
OpenStudy (kgrendel0324):
now you have 3y > 2x - 1, you want to get y by itself
OpenStudy (kgrendel0324):
divide three from both sides and you get y<2/3x -1/3
OpenStudy (kgrendel0324):
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OpenStudy (abbycross167):
okay what do I do next?
OpenStudy (kgrendel0324):
well thats the graph completed right there. what do you need?
OpenStudy (abbycross167):
I need all of the steps... I want to know the steps for this that way I can try to learn how to do it
OpenStudy (kgrendel0324):
okay
OpenStudy (kgrendel0324):
well there are multiple way to graph this. you want a table?
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OpenStudy (kgrendel0324):
or an actual graph
OpenStudy (kgrendel0324):
nvm that im going ot assume its a graph you want.
OpenStudy (kgrendel0324):
so you want to turn this equation 3y > 2x - 1 into slope-intercept form
OpenStudy (abbycross167):
umm well I guess a ghaph? But could you explain the steps ? please?
OpenStudy (kgrendel0324):
yeah
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OpenStudy (kgrendel0324):
so when you put this 3y > 2x - 1 in slope-int form you get y>2/3x-1/3
OpenStudy (kgrendel0324):
do you understand that?
OpenStudy (kgrendel0324):
or how you do that?
OpenStudy (abbycross167):
ma'am/sir I want to graph -1/2 + (1/2)y >= x ....
OpenStudy (kgrendel0324):
oh.... my bad.. idk what i was looking at...
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OpenStudy (abbycross167):
its okay, would you still be able to help me?
OpenStudy (kgrendel0324):
hold on, i have to look at this one
OpenStudy (abbycross167):
okay
OpenStudy (kgrendel0324):
idk
OpenStudy (kgrendel0324):
im srry
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OpenStudy (abbycross167):
okay, thank you very much for trying